De
la
actividad
anterior
,
definimos
que
:
2a
=
4
3a
+
b
=
3
a
+
b
+
c
=
3
A
partir
de
esto
,
podemos
obtener
a
,
b
y
c
despejando
:
2a
=
____________________
a
=
____________________
/
2
a
=
____________________
3a
+
b
=
____________________
3
(
____________________
)
+
b
=
____________________
____________________
+
b
=
3
b
=
____________________
-
____________________
b
=
-
____________________
a
+
b
+
c
=
____________________
(
____________________
)
+
(
-
____________________
)
+
c
=
____________________
____________________
-
____________________
+
c
=
3
-
____________________
+
c
=
____________________
c
=
____________________
+
____________________
c
=
____________________
an^2
+
bn
+
c
=
2n^2
-
____________________
+
4
