5x – 3 = 12
2 x – 11 = – 9
5x – 3 ≥ 12
5x - 10 = 5(x - 2)
– πx + 4π < π
-x< 1
π x + 4 π = π
– 4x – 15 > – 2x – 11
...
V = {3}
V = ]-∞, -2]
V = {1}
V = [3, +∞[
V = ∅
V = ]-1, +∞[
V = ]3, +∞[
V = {-3}
V = |R
