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Map Quiz
Map Quiz

DESPEJANDO VARIABLES DE LOS GASES.

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DESPEJANDO VARIABLES DE LOS GASES.

Map Quiz

(2)
Haz clic en el cuadro que tiene la fórmula de la variable despejada de la fórmula general que se solicita.

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About Map Quiz
gases
 Recommended age: 14 years old
368 times made

Created by

Luis Antonio Muñoz
Luis Antonio Muñoz
Colombia

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DESPEJANDO VARIABLES DE LOS GASES.Online version

Haz clic en el cuadro que tiene la fórmula de la variable despejada de la fórmula general que se solicita.

by Luis Antonio Muñoz
1 Ley de Boyle - Mariote, la T es constante (V1P2 = V2P1). El volumen inicial es. 2 Ley de Boyle - Mariote, la T es constante (V1P2 = V2P1). El volumen final es. 3 Ley de Boyle - Mariote, la T es constante (V1P2 = V2P1). La presión inicial es. 4 Ley de Boyle - Mariote, la T es constante (V1P2 = V2P1). La presión final, es. 5 Ley de Charles, P es constante (V1T2 = V2T1). Volumen inicial es: 6 Ley de Charles, P es constante (V1T2 = V2T1). Volumen final es: 7 Ley de Charles, P es constante (V1T2 = V2T1). Temperatura inicial es: 8 Ley de Charles, P es constante (V1T2 = V2T1). Temperatura final es: 9 Ley de Gay - Lussac, V es constante ( P1T2 = P2T1). Presión inicial es: 10 Ley de Gay - Lussac, V es constante ( P1T2 = P2T1). Presión final es: 11 Ley de Gay - Lussac, V es constante ( P1T2 = P2T1). Temperatura inicial es: 12 Ley de Gay - Lussac, V es constante ( P1T2 = P2T1). Temperatura final es: 13 En la ley combinada de los gases V1P1/T1 = V2P2/T2. Volumen inicial es: 14 En la ley combinada de los gases V1P1/T1 = V2P2/T2. Volumen final es: 15 En la ley combinada de los gases V1P1/T1 = V2P2/T2. presión inicial es: 16 En la ley combinada de los gases V1P1/T1 = V2P2/T2. presión final es: 17 En la ley combinada de los gases V1P1/T1 = V2P2/T2. Temperatura inicial es: 18 En la ley combinada de los gases V1P1/T1 = V2P2/T2. Temperatura final es: 19 En la ecuación de estado de los gases ideales PV =nRT. La presión es: 20 En la ecuación de estado de los gases ideales PV =nRT. El volumen es: