Guided Series 1 (D) (D)Online version Check the video, copy the series on your notebook and answer it while looking the explanations and questions related to the series by Brandon Ortiz Casas 1 Select the compound that correspond to compound 'B' of the guided series Select one or more answers a 2-chloro-3-methylbutane b 1-chloro-2-methylbutane c 2-chloro-2-methylbutane 2 Select the compound that correspond to compound 'C' of the guided series Select one or more answers a 2-methyl-1-butene b 2-methyl-2-butene c 3-methyl-1-butene 3 Select the compound that correspond to compound 'D' of the guided series Select one or more answers a 2-methyl-2-butanol b 3-methyl-2-butanol c 2-methyl-1-butanol 4 Select the compound that correspond to compound "E" of the guided series Select one or more answers a 1,2-dibromo-2-methylbutane b 2,3-dibromo-2-methylbutane c 2-bromo-2-methylbutane Explanation 1 The tertiary carbon contains a tertiary hydrogen that more preferentially gets substituted by a halogen. 2 The alpha carbon contains the halogen, and the beta carbons are the direct neighbor to the alpha carbon. The double bond forms between the alpha carbon and the beta carbon with the least amount of hydrogens. 3 Apply Markovnikov's Rule to know the location of the "H", that should bond to the carbon of the double bond that has the most amount of hydrogens, and thus OH bonds to the other carbon 4 Because molecule "C" is an alkene, an addition reacts on the double bond, adding a bromine on both sides (carbons) of the double bond
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