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Dinámica de un snorlax

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Dinámica de un snorlax

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About this activity

En esta actividad descubriremos como funciona la dinámica en un plano inclinado

Created by

Maicol
Maicol
Uruguay

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Dinámica de un snorlax
 

Dinámica de un snorlaxOnline version

En esta actividad descubriremos como funciona la dinámica en un plano inclinado

by Maicol
1 El ángulo de inclinación es de 45° 2 ¿De qué valor es el módulo del peso de snorlax? 3 Cuanto vale la fuerza de fricción estática 4 ¿Cuánto vale la normal?

Explicación

Recordemos que F=m.a, si la masa de snorlax es de 460kg y la aceleración es debido a la gravedad, entonces el modulo del peso es: P=(460kg)×(9.8m/s²)= 4508N

La fuerza de fricción la podemos calcular ya que debe ser igual a la componente horizontal de la fuerza peso, esto es F=Psen(45°)= 4508 × sen(45°)≈3188N

Al igual que con la fuerza de fricción, podemos calcular la fuerza normal al plano a partir del peso de la siguiente manera: N=Pcos(45°)=(4508N)×(cos(45°))≈3188N

 
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