Digital Design True/False Challenge

Yes or No

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Quick true/false quiz on combinational logic concepts.

Created by

Owais Alhgahmed

Palestine

Download the paper version to play

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Digital Design True/False ChallengeOnline version Quick true/false quiz on combinational logic concepts. by Owais Alhgahmed 1 A 3-state gate guarantees a defined output of 0 or 1 even when it is disabled. Yes No 2 In a 4-bit adder/subtractor using two's complement, the final carry can be ignored for subtraction. Yes No 3 For subtraction A - B using two's complement, compute A + (2's complement of B). Yes No 4 A 3-state gate can be wired together with other gates, but at most one gate can be enabled at a time to avoid conflicts. Yes No 5 A 7-segment decoder outputs the same pattern for all input codes regardless of the BCD value. Yes No 6 The final carry in an n-bit adder is never used or considered for any operation. Yes No 7 A ripple-carry adder propagates the carry from least significant to most significant through each full adder. Yes No 8 A combinational circuit's outputs are determined only by the present inputs. Yes No 9 A 2-to-4 decoder has no enable input and always activates one of its outputs. Yes No 10 A ripple-carry adder has a constant delay regardless of the number of bits. Yes No

Digital Design True/False ChallengeOnline version

Quick true/false quiz on combinational logic concepts.

by Owais Alhgahmed

A 3-state gate guarantees a defined output of 0 or 1 even when it is disabled.

Yes

In a 4-bit adder/subtractor using two's complement, the final carry can be ignored for subtraction.

Yes

For subtraction A - B using two's complement, compute A + (2's complement of B).

Yes

A 3-state gate can be wired together with other gates, but at most one gate can be enabled at a time to avoid conflicts.

Yes

A 7-segment decoder outputs the same pattern for all input codes regardless of the BCD value.

Yes

The final carry in an n-bit adder is never used or considered for any operation.

Yes

A ripple-carry adder propagates the carry from least significant to most significant through each full adder.

Yes

A combinational circuit's outputs are determined only by the present inputs.

Yes

A 2-to-4 decoder has no enable input and always activates one of its outputs.

Yes

A ripple-carry adder has a constant delay regardless of the number of bits.

Yes

You can integrate the game into an LMS compatible with LTI 1.1 or LTI 1.3 such as Canvas, Moodle, or Blackboard. This way, the scores will be automatically saved into the platform’s gradebook.

Digital Design True/False Challenge

Yes or No

About this activity

Created by

Download the paper version to play

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Yes or No

Adjective Checker

Yes or No

Grammys for best song/record

Yes or No

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Yes or No

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Yes or No

Foot and Ankle Anatomy Quiz

Digital Design True/False ChallengeOnline version

by Owais Alhgahmed

A 3-state gate guarantees a defined output of 0 or 1 even when it is disabled.

In a 4-bit adder/subtractor using two's complement, the final carry can be ignored for subtraction.

For subtraction A - B using two's complement, compute A + (2's complement of B).

A 3-state gate can be wired together with other gates, but at most one gate can be enabled at a time to avoid conflicts.

A 7-segment decoder outputs the same pattern for all input codes regardless of the BCD value.

The final carry in an n-bit adder is never used or considered for any operation.

A ripple-carry adder propagates the carry from least significant to most significant through each full adder.

A combinational circuit's outputs are determined only by the present inputs.

A 2-to-4 decoder has no enable input and always activates one of its outputs.

A ripple-carry adder has a constant delay regardless of the number of bits.

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