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Problema fisica 3

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Problema fisica 3

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Problema fisica 3

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Problema fisica 3
 

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Problema fisica 3Online version

Problema fisica 3

by Jaime Alarcón González
1

Una vasija A de 200 cm3 está separada de otra B de 600 cm3mediante una tubería de capacidad despreciable , provista de una llave de paso . La vasija A contiene un gas a 750 mmHg y en la B se ha hecho el vacío . Calcula la presión en los dos recipientes después de abrir la llave de paso , si no varía la temperatura .
A 200 cm3 B 600 cm3

varía la temperatura , hay que la ley de Boyle - Mariotte ( p1· V1 = p2 ·V2 ) .


800 cm3 porque , los tienden a ocupar todo el espacio disponible , y el gas
que estaba antes en la vasija A está ahora en las dos vasijas .

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