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تحدي محيط الدائرة

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حسابات محيط الدائرة للصف السادس

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Libya

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تحدي محيط الدائرة
 

تحدي محيط الدائرةOnline version

حسابات محيط الدائرة للصف السادس

by Najlaa Alkammoshi
1

محيط الدائرة يساوي 2 × باي × نصف القطر.

2

إذا كان نصف القطر 5 سم، المحيط 50 سم.

3

المحيط لا يعتمد على ثابت باي عند تغيّر القطر.

4

بإعطاء نصف القطر 7 سم، المحيط ≈ 43.96 سم باستخدام باي تقريبي 3.14.

5

محيط الدائرة يساوي 2 × نصف القطر فقط.

6

المحيط الدائرة يساوي القطر مضروباً في 2.

7

المحيط يساوي قيمة ثابت باي مضروبة بالقطر.

8

إذا كان نصف القطر r، فالمحيط = 2·باي·r.

9

المحيط يساوي القطر مقسومًا على باي.

10

محيط الدائرة يساوي باي × القطر.

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