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S2_Teoría de Máq-Recurso Digital

Video Quiz

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S2_Teoría de Máq-Recurso Digital
 

S2_Teoría de Máq-Recurso DigitalOnline version

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by soporteucvirtual UCVirtual
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1

¿Por qué se denomina falla por fatiga?

2

¿Qué ocurre en la etapa dos de una falla por fatiga?

3

Si un elemento tiene σmáx = 120 MPa y σmín = 40 MPa, ¿cuál es el esfuerzo alterno?

4

¿Por qué el límite de resistencia a la fatiga de una pieza real suele ser menor que el obtenido en laboratorio?

Explicación

Recurda: El video explica que la característica principal de la fatiga es la repetición continua de esfuerzos durante un gran número de ciclos, lo que termina provocando la fractura.

Recuerda: En la segunda etapa, las microgrietas evolucionan a macrogrietas y se forman superficies características con marcas de playa.

Recuerda: El esfuerzo alterno se calcula como: σa = (σmáx − σmín) / 2 Por tanto: (120 − 40) / 2 = 40 MPa.

Recuerda: El video indica que factores como el acabado superficial, tamaño, carga, temperatura y entorno modifican el comportamiento real de la fatiga respecto al ensayo de laboratorio.

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