Inverse Proportion Scanner

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Grade 7 YES/NO: inverses

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Hidden Author

Lebanon

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Inverse Proportion ScannerOnline version Grade 7 YES/NO: inverses by Hidden Author 1 10. For the belt example, 8 × 400 = 3 200. Yes No 2 1. If 8 belts share K3 200 equally, each belt costs K400. Yes No 3 2. K3 200 ÷ 8 = K400. Yes No 4 5. When the number of belts changes from 8 to 16, it doubles. Yes No 5 12. In this inverse relationship, the product remains constant. Yes No 6 9. In inverse proportion, one quantity can increase while the other decreases. Yes No 7 3. If 16 belts share K3 200 equally, each belt costs K200. Yes No 8 4. K3 200 ÷ 16 = K200. Yes No 9 7. K200 is half of K400. Yes No 10 8. In inverse proportion, both quantities always increase together. Yes No 11 11. For the same example, 16 × 200 = 3 200. Yes No 12 6. When the number of belts doubles from 8 to 16, the cost per belt changes from K400 to K200. Yes No

Inverse Proportion ScannerOnline version

Grade 7 YES/NO: inverses

by Hidden Author

10. For the belt example, 8 × 400 = 3 200.

Yes

1. If 8 belts share K3 200 equally, each belt costs K400.

Yes

2. K3 200 ÷ 8 = K400.

Yes

5. When the number of belts changes from 8 to 16, it doubles.

Yes

12. In this inverse relationship, the product remains constant.

Yes

9. In inverse proportion, one quantity can increase while the other decreases.

Yes

3. If 16 belts share K3 200 equally, each belt costs K200.

Yes

4. K3 200 ÷ 16 = K200.

Yes

7. K200 is half of K400.

Yes

8. In inverse proportion, both quantities always increase together.

Yes

11. For the same example, 16 × 200 = 3 200.

Yes

6. When the number of belts doubles from 8 to 16, the cost per belt changes from K400 to K200.

Yes

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Inverse Proportion Scanner

Yes or No

About this activity

Created by

Download the paper version to play

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Yes or No

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Yes or No

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Inverse Proportion ScannerOnline version

by Hidden Author

10. For the belt example, 8 × 400 = 3 200.

1. If 8 belts share K3 200 equally, each belt costs K400.

2. K3 200 ÷ 8 = K400.

5. When the number of belts changes from 8 to 16, it doubles.

12. In this inverse relationship, the product remains constant.

9. In inverse proportion, one quantity can increase while the other decreases.

3. If 16 belts share K3 200 equally, each belt costs K200.

4. K3 200 ÷ 16 = K200.

7. K200 is half of K400.

8. In inverse proportion, both quantities always increase together.

11. For the same example, 16 × 200 = 3 200.

6. When the number of belts doubles from 8 to 16, the cost per belt changes from K400 to K200.

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