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About this activity

This is a fundamental quiz on Linked List belonging to Linear Data Structure

Created by

Aditi Sen
Aditi Sen
India

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Linked ListOnline version

This is a fundamental quiz on Linked List belonging to Linear Data Structure

by Aditi Sen
1

A list can be described as a

Choose one or more answers

2

Value-ordered lists are frequently referred to as

3

Which of the following options are true? Choose two correct options.

Choose one or more answers

4

A list of students, named, 'lstStudents', needs to be ordered numerically by their roll numbers. Which of the following options is NOT TRUE in this regard?

5

Figure : Linear Linked List with 3 nodes Note : Head is a pointer variable containing address of the first node. For each node, first part contains information/value of the node, second part called 'nextpointer field' contains address of next node. What does X signify in the given figure?Choose two correct options.

Choose one or more answers

6

Identify the correct option to create an Empty singly Linked List. Note: A Singly Linked List has a data part and a nextpointer field pointing to next Node.

7

Jay is moving along the pointers of a singly Linked List till he reaches the last element and is using a Stack to store pointers to these individual elements of the list. Then he is printing the contents of the memory locations to which these pointers are pointing. What is Jay trying to achieve here?

8

Identify the applications of Linked Lists from the following.

Choose one or more answers

9

What does the pseudocode given below is trying to achieve? Note: tempNode is any Node , head is a pointer variable pointing to first node of a Linked List. if(head==null): tempNode.nextPointer = NULL; else tempNode.nextPointer=head; head.next=tempNode;

10

What does the pseudocode given below is trying to achieve? Note: tempNode is any Node , head is a pointer variable pointing to first node of a Linked List. tempNode.previousPointer=NULL; if(head==null): tempNode.nextPointer = NULL; else head.next.previousPointer=tempNode; tempNode.nextPointer=head; head.next=tempNode;

11

Given the pseudocode below, choose the options that are NOT correct. while head!=null: temp = head; head = head.next; free(temp); tail = NULL; Note: temp is a temporary variable

Choose one or more answers
 
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