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Área de Figuras Planas, Plano Cartesiano, Teorema de Pitágoras y Ecuación

Created by

Andres fernando Camargo molano
Andres fernando Camargo molano
Colombia

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Área de Figuras Planas, Plano Cartesiano, Teorema de Pitágoras y Ecuación

by Andres fernando Camargo molano
1

El área de un cuadrado de lado 6cm es:

2

El punto (0,0) en el plano cartesiano se llama:

3

El Teorema de Pitágoras se aplica a:

4

Resolver: x + 5 = 12 → x =

5

El área de un triángulo de base 8 cm y altura 5 cm es:

6

El punto (4, -3) se encuentra en el cuadrante:

7

Si un triángulo tiene catetos 3 y 4, la hipotenusa mide:

8

Resolver: 3x = 21 → x =

9

El área de un rectángulo de 10 cm × 4 cm es:

10

En el punto (5,7), el número 5 representa:

11

Si la hipotenusa es 13 y un cateto es 12, el otro cateto mide:

12

Resolver: 2x - 4 = 10 → x =

13

El área de un círculo con radio 7 cm (π=3,14) es:

14

El eje horizontal del plano cartesiano es:

15

Fórmula del Teorema de Pitágoras:

16

Resolver: x/4 = 6 → x =

17

El área de un paralelogramo de base 12 cm y altura 6 cm es:

18

Si un punto está en el eje Y, su abscisa siempre es:

19

Si un cateto mide 8 y la hipotenusa 17, el otro cateto mide:

20

Resolver: 5x + 2 = 17 → x =

 
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