New game
Download
Get Academic Plan
Share game
Integrate it into your platform

You can integrate the game into an LMS compatible with LTI 1.1 or LTI 1.3 such as Canvas, Moodle, or Blackboard. This way, the scores will be automatically saved into the platform’s gradebook.
Download
You have exceeded the maximum number of games you can integrate into Google Classroom with your current Plan.

To integrate as many games as you want in Google Classroom, you need an Academic Plan or a Commercial Plan.

You have exceeded the maximum number of games you can integrate into Microsoft Teams with your current Plan.

To integrate as many games as you want in Microsoft Teams, you need an Academic Plan or a Commercial Plan.

Downloading games is an exclusive feature for users with an Academic Plan or a Commercial Plan.

Get your Academic Plan or your Commercial Plan now and start integrating your games into your LMS, website or blog.

If you wish, you can download a demo game here and test its integration:

Movimientos de Proyectiles

Quiz

Played 2

About this activity

Quiz rápido sobre fórmulas de proyectiles.

Created by

Colombia

Download the paper version to play

Make your own free game from our game creator
Compete against your friends to see who gets the best score in this game

Top Games

%
Anonymous
Anonymous
%
%
%
You have exceeded the maximum number of games you can print with your current Plan.

To print as many games as you want, you need an Academic Plan or a Commercial Plan.

Print your game
Movimientos de Proyectiles
 

Movimientos de ProyectilesOnline version

Quiz rápido sobre fórmulas de proyectiles.

by Juan Camilo Romero
1

¿Qué expresa D en función de Vo, β y g?

2

¿Cuál es la fórmula de la altura máxima H?

3

Tiempo de vuelo tv = ?

4

Si β = 0, ¿qué pasa con D?

5

Dado Vo=20, β=45°, g=9.8, D vale…

6

Si β = 90°, H es:

7

Con Vo=15 m/s, β=30°, g=9.8, tv ≈

8

Para β=0°, ¿qué ocurre con H?

9

Relación D/H para Vo y g fijos es:

10

Qué factor afecta mayormente H?

Explicación

D usa sen(2β); otras fórmulas no dan distancia horizontal.

H depende de sen^2β; g está en el denominador correcto.

El tiempo depende de la componente vertical inicial.

β = 0 no hay elevación, distancia cero.

Sin 90° para sen(2β)=1, D ≈ Vo^2/g.

Sen^2β = 1 cuando β=90°; D y tv quedan different.

tv = 2*15*sin30 / 9.8 ≈ 1.53 s.

Sin elevación, la altura es cero.

D/H = (Vo^2/g · sin2β)/(Vo^2/g · sin^2β) = 2 cotβ.

H depende de sen^2β; mayor incremento cuando senβ aumenta.

Are you sure you want to leave the page?

If you leave the page, you will lose your game progress.