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Desafío Matemático: Repartos y Edades

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Desafío Matemático: Repartos y Edades

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Problemas con respuestas claras

Created by

JOHAN GABRIEL BALAM UUH
JOHAN GABRIEL BALAM UUH
Mexico

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Desafío Matemático: Repartos y Edades
 

Desafío Matemático: Repartos y EdadesOnline version

Problemas con respuestas claras

by JOHAN GABRIEL BALAM UUH
1

En el reparto de naranjas, si José recibe x y Ana recibe x+40, con total 290, ¿cuántas recibe José?

2

En la herencia, hermano pequeño=x, mediano=4x, mayor=8x. Si la suma es 1,300,000, ¿cuánto obtiene el hermano pequeño?

3

Edad padre/hijo: si el padre será 3 veces la edad del hijo en x años, y actuales son 47 y 11, ¿cuántos años deben transcurrir?

4

Sueldo de Carlos: base x y comisión por 200 libros es 1200, total 2500. ¿Cuál es la base semanal?

5

Medidas de la pared: beige=x, lila=x+1.5, turquesa=x+2.5; suman 9. ¿Cuánto mide la beige en metros?

6

En el reparto de naranjas, ¿cuántas recibe Ana si José recibe 125 y Ana 40 más?

7

En la herencia, ¿cuánto recibe el hermano mayor?

8

Edad del hijo dentro de 5 años, si ahora tiene 11 años, ¿cuántos tendrá?

9

¿Cuánto es la comisión por 150 libros si 200 libros dan 1200, y total es 2500?

10

¿Cuánto mide la parte lila en metros, sabiendo x=5/3 y lila=x+1.5?

Explicación

Resolver 2x+40=290 → x=125.

13x=1,300,000 → x=100,000.

47+x=3(11+x) → 14=2x → x=7.

x+1200=2500 → x=1300.

3x+4=9 → x=5/3.

Ana = 125+40 = 165.

Mayor recibe 8x = 8*100000 = 800000.

11+5=16.

Proporción: comisión = 1200*(150/200)=900.

x+1.5 = 5/3 + 3/2 = 19/6.

 
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