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Electrochemical Potentials Challenge

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Practice reduction potential problems

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United Arab Emirates

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Electrochemical Potentials Challenge
 

Electrochemical Potentials ChallengeOnline version

Practice reduction potential problems

by Areen Okour
1

1) Given E°(Cu2+/Cu)=0.34 V and E°(Zn2+/Zn)=-0.76 V, what is E°cell for Zn|Zn2+ // Cu2+|Cu?

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3) Which electrode is the cathode for the Zn|Zn2+ // Cu2+|Cu cell?

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4) What is the general formula for E°cell?

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7) Which pair gives a larger E°cell: Fe2+/Fe (-0.44 V) with Cu2+/Cu (0.34 V)

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8) A spontaneous galvanic cell has E°cell that is

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9) What is the SI unit for electrode potential?

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10) Reversing the electrodes of a cell will

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Cu has higher E°, so Cu2+/Cu is cathode; E°cell = 0.34 - (-0.76) = 1.10 V.

Cathode is the half-reaction with higher reduction potential.

Reduction potentials subtract: cathode minus anode.

E°cell = 0.34 - (-0.44) = 0.78 V.

Spontaneity corresponds to E°cell > 0.

Electrode potentials are measured in volts.

Switching anode/cathode flips E°cell sign.

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