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Cinemática: Velocidad, Distancia y Tiempo (Resolución de Problemas)

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Cuestionario de problemas con conversiones

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Ecuador

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Cinemática: Velocidad, Distancia y Tiempo (Resolución de Problemas)
 

Cinemática: Velocidad, Distancia y Tiempo (Resolución de Problemas)Online version

Cuestionario de problemas con conversiones

by Adela Paspuel
1

Caso 1 Un repartidor de pizza viaja del Tena al Pano una distancia de 5 millas ( 1milla =1,61km) porfavor hallar tiempo si la velocidad es 40 km/h. ¿Cuánto tarda en minutos (aprox.)?

2

Caso 1: Si el repartidor viaja una distancia de 8.0 millas del Tena al Pano a una velocidad de 60 km/h, ¿cuánto tarda en minutos?

3

Caso 2 (El atleta): Velocidad 3.5 m/s y tiempo 1 h 20 m. Distancia en km.

4

Caso 2: Velocidad 5 m/s durante 15 minutos. Distancia en km.

5

Despeje: Si v = d/t, ¿qué despeje da para d?

6

Despeje: D = v t, ¿qué despeje da para t?

7

Conversión de tiempo: 2 h 30 m a segundos.

8

Conversión de longitud: 3 km a m.

9

Caso 2: Si D = 2.2 km y v = 4 m/s, ¿t? (en minutos)

Explicación

Conversión: 5 millas ≈ 8.05 km. Tiempo t = d/v = 8.05/40 h = 0.20125 h ≈ 12.1 minutos.

Conversión: 8.0 millas ≈ 12.88 km. t = d/v = 12.88/60 h = 0.2147 h ≈ 12.9 min.

Convierte tiempo a s: 1 h 20 m = 4800 s. D = v t = 3.5 × 4800 = 16800 m = 16.8 km. Nota: pregunta pide km, corregido: 16.8 km.

Tiempo 15 min = 900 s. D = 5×900 = 4500 m = 4.5 km.

Reorganiza v = d/t -> d = v t. El orden correcto es multiplicar t por v.

Despeje t: t = d/v, manteniendo v ≠ 0.

1 h = 3600 s; 2 h = 7200 s; 30 m = 1800 s; total 9000 s.

1 km = 1000 m. 3 × 1000 = 3000 m.

Convertir D a m: 2200 m. t = D/v = 2200/4 = 550 s ≈ 9.17 min.

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