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Balanceo de Ecuaciones Químicas por Método Redox y Algebraico

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Balanceo de Ecuaciones Químicas por Método Redox y Algebraico

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Balanceo por métodos redox y algebraico

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María Lorena Loaiza
María Lorena Loaiza
Ecuador

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Balanceo de Ecuaciones Químicas por Método Redox y Algebraico
 

Balanceo de Ecuaciones Químicas por Método Redox y AlgebraicoOnline version

Balanceo por métodos redox y algebraico

by María Lorena Loaiza
1

¿Qué método aplica cuando se equilibra por pares de semireacciones?

2

Con base en la reacción, determine el agente reductor: FeCl2 + H2O2 + HCl → FeCl3 + H2O

3

Iguale por redox la ecuación: HNO3 + Zn → Zn (NO3)2 + NH4 (NO3) + H2O

4

Con base en la ecuación redox, ¿Cuál especie química es el agente oxidante? Cr(OH)3 + NaClO + Na2OH3 ↔ Na2CrO4 + NaCl + H2O

5

Seleccione las reacciones que cumplen con la ley de la conservación de la materia: 1: CH4 + O2 → CO2 + H2O 2: 2 H2 + O2 → 2 H2O 3: C + O2 → CO 4: N2 + 3 H2 → 2 NH3 5: Na(OH) + HCl → NaCl + H2O

6

Iguale por el método algebraico la siguiente ecuación: Fe+HBr→FeBr3​+H2​

7

¿Cuál es el agente reductor? En la siguiente reacción: Mg+HCl→MgCl2​+H2​

8

En la reacción: Zn+CuSO4​→ZnSO4​+Cu a) ¿Quién se oxida? b) ¿Quién se reduce? c) ¿Agente oxidante?

9

En la reacción: ​ H2​O2​+I- →I2​+H2​O ​a) ¿Quién es el agente oxidante? b) ¿Quién es el agente reductor?

10

Balancea por método algebraico: C2​H6​+O2​→CO2​+H2​O

 
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