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Asas Black: Kalor & Suhu

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Asas Black: Kalor & Suhu

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Kuis tentang kalor, perubahan suhu, dan asas Black

Created by

Nafiska Sayekti Ariyani
Nafiska Sayekti Ariyani
Indonesia

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Asas Black: Kalor & Suhu
 

Asas Black: Kalor & SuhuOnline version

Kuis tentang kalor, perubahan suhu, dan asas Black

by Nafiska Sayekti Ariyani
1

1) Campuran air 200 g (80°C) dengan air 100 g (20°C). Suhu akhir yang mungkin?

2

2) Air 100 g dari 20°C ke 50°C. Kalor total yang dibutuhkan?

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3) Sesuai contoh, jika dua benda massa sama, A naik 20°C dan B naik 10°C dengan kalor sama. Perbandingan c_A : c_B = ?

4

4) Air 100 g (80°C, c=4,2) dicampur zat 100 g (20°C, c=2,1). Suhu akhirnya?

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5) Air 200 g dipanaskan 20→40°C lalu ke 60°C. Kalor total?

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6) Jika jumlah air panas > air dingin, suhu akhir cenderung mendekati?

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7) Dua benda A (c kecil) dan B (c besar) diberi kalor sama. Mana yang naik suhu lebih besar?

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8) Air 300 g pada 60°C dicampur air 100 g pada 20°C. Suhu akhir?

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9) Air dipanaskan 100 g dengan ΔT = 10°C butuh Q berbanding?

10

10) Campuran air 200 g pada 70°C dan 200 g pada 30°C, lalu dipanaskan +10°C. Kalor tambahan?

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Hits: panas yang hilang = panas yang diperoleh; hasilnya 60°C.

Q = m c ΔT = 100×4,2×30 = 12600 J.

ΔT ∝ 1/c, jadi c_B = 2 c_A.

Setara panas: 100×4,2×(80−T) = 100×2,1×(T−20) → T ≈ 60°C.

Q_total = 200×4,2×20 + 200×4,2×20 = 33600 J.

Suhu akhir mendekati suhu air yang lebih banyak.

ΔT = Q/(m c); dengan c lebih kecil, ΔT lebih besar pada A.

Rata-rata termal: T_f = (300×60 + 100×20)/400 = 50°C.

Q = 100×4,2×10 = 4200 J; jika massa 200 g, jadi 2Q.

Suhu akhir 50°C; Q = m c ΔT = 400×4,2×10 = 16800 J.

 
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