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Áreas sombreadas

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Áreas sombreadas

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Quiz de áreas en figuras

Created by

Juan Pablo Meléndez Erazo
Juan Pablo Meléndez Erazo
Colombia

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Áreas sombreadas
 

Áreas sombreadasOnline version

Quiz de áreas en figuras

by Juan Pablo Meléndez Erazo
1

En un rectángulo exterior de 10 cm por 6 cm, se recorta un rectángulo interior de 4 cm por 2 cm. ¿Cuál es el área sombreada?

2

Un círculo de radio 5 cm tiene un sector de 60° sombreado. ¿área sombreada?

3

Trapecio isósceles con bases 8 y 3 y altura 4. ¿área sombreada?

4

Cuadrado de 12 cm por lado con recorte cuadrado de 4 cm en una esquina. Área sombreada?

5

Un semicírculo de radio 10 cm sombreado. ¿área?

6

Anillo con radio exterior 7 cm y radio interior 3 cm. ¿área sombreada (anillo)?

7

Rectángulo 9 cm por 5 cm con una sombra que es un triángulo de base 3 cm y altura 4 cm eliminado. ¿área sombreada?

8

Rectángulo con lados 6 cm y 8 cm sombreado como el área del triángulo interior. ¿área?

9

Paralelogramo base 7 cm y altura 4 cm. ¿área sombreada?

10

Círculo de radio 4 cm sombreado como semicircunferencia. ¿área?

Explicación

La sombrea es 60-8=52 cm²; los otros valores no restan el recorte correctamente.

Área del sector = (60/360)·π·5² ≈ 13.09 cm²; los demás son fracciones incorrectas.

Área = ((8+3)/2)·4 = 22 cm²; otros resultados no aplican la fórmula.

Área sombreada = 12² − 4² = 144 − 16 = 128 cm²; los demás son errores de cálculo.

Área semicircular = (π·10²)/2 ≈ 157.08 cm²; otros valores corresponden a mitades o círculos completos mal aplicados.

Área = π(7²−3²) = 40π ≈ 125.66 cm²; los distractores no usan la diferencia de radios.

Área total 45 cm² menos triángulo 6 cm² da 39 cm²; otros resultados son errores.

Área del triángulo = 0.5·6·8 = 24 cm²; distractores son otras multiplicaciones.

Área = base·altura = 7·4 = 28 cm²; otros son errores de base o altura.

Área semicircular = (π·4²)/2 = 8π ≈ 25.13 cm²; otros valores son mitades mal calculadas.

 
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