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Quiz: Vértice de la parábola

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Quiz: Vértice de la parábola

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Vértice y forma de la parábola

Created by

Cecilia Gabriela Cortez Nochez
Cecilia Gabriela Cortez Nochez
El Salvador

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Quiz: Vértice de la parábola
 

Quiz: Vértice de la parábolaOnline version

Vértice y forma de la parábola

by Cecilia Gabriela Cortez Nochez
1

1) Dada y = 2x^2 - 8x + 3, ¿ dónde está el vértice?

2

2) Para y = -x^2 + 4x + 1, ¿cuál es el vértice?

3

3) Convierte y = 3x^2 -12x +7 a la forma vértice. ¿ cuál es el vértice?

4

4) ¿Qué condición debe cumplir 'a' para que sea una parábola?

5

5) Sea y = 0.5x^2 - x + 4. ¿Dónde está el vértice?

6

6) Para y = x^2 + 4x + 5, ¿cuál es el vértice?

7

7) Verdadero o Falso: el vértice se obtiene siempre al completar el cuadro (forma vértice).

8

8) Si a=2 y b=-8, ¿cuál es la ecuación de la recta de simetría (axisa del vértice)?

9

9) Para y = -3x^2 + 6, ¿dónde está el vértice?

10

10) Si y = 4x^2 -4x +1, ¿qué vértice tiene?

Explicación

Usa h = -b/(2a) y k = f(h). Aquí h=2 y k=-5.

h = -b/(2a) = -4/(2·-1) = 2; k = f(2) = 5.

Completa el cuadrado: h = -b/(2a) = 12/6 = 2; k = f(2) = -5.

Si a = 0, ya no es una parábola (se obtiene una recta).

h = -b/(2a) = 1; k = f(1) = 0.5 -1 +4 = 3.5.

h = -b/(2a) = -4/2 = -2; k = f(-2) = 1.

Completar el cuadrado lleva a la forma y el vértice.

h = -b/(2a) = -(-8)/(4) = 2; eje de simetría x = 2.

h = -0/(2·-3) = 0; k = f(0) = 6.

h = -b/(2a) = 4/(8) = 0.5; k = f(0.5) = 0.

 
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