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Grade 5 Math Quest

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Grade 5 Math Quest

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Fifth grade math challenge

Created by

margaret
margaret
France

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Grade 5 Math Quest
 

Grade 5 Math QuestOnline version

Fifth grade math challenge

by margaret
1

If x = 4, what is 7x?

2

Evaluate (3 + 6) × 2.

3

Compute 3/4 + 1/2.

4

Convert 2 3/5 to an improper fraction.

5

Compute 9 × 8.

6

4629 ÷ 7 equals what quotient?

7

In a line plot, which value is most common if there are five 0s, three 1s, and two 2s?

8

Which is larger, 3/5 or 4/7?

9

Convert 4 1/6 to an improper fraction.

10

What is the range of values on a line plot with smallest 0 and largest 3?

11

Interpreting line plots: If 7 students have heights 60-65 inches on a line plot, what can you infer about the data set's central tendency?

12

Long division: What is 784 ÷ 7?

13

One-step algebra: If x + 5 = 12, what is x?

14

Order of operations: Evaluate 3 + 4 × 2.

15

Area of rectangle: Length 9 cm, width 4 cm. Area?

16

Line plots: If numbers 2,2,3,3,3,4 are on the plot, which value occurs most?

17

Long division: 455 ÷ 5 equals?

18

Algebra: Solve for y in 2y = 14.

19

Order of operations: Evaluate 6 ÷ 2(1+2).

20

Area of rectangle: If perimeter is 26 cm and length is 7 cm, find width. (Area not required)

Feedback

Multiplying 7 by 4 gives 28.

First add inside the parentheses, then multiply.

Convert 1/2 to 2/4 and add to 3/4 = 5/4.

Multiply 2 by 5 and add 3 to get 13/5.

9 times 8 equals 72.

7 × 661 = 4627; remainder 2, quotient 661.

0 appears the most with five occurrences.

0.6 vs ≈0.571; 3/5 is larger.

4×6 + 1 = 25, so 25/6.

Range = largest − smallest = 3 − 0 = 3.

Line plots show where data cluster. A central tendency near the middle class (around 62-63) is typical for such data. The data aren’t all equal or extreme.

7 goes into 7 once, into 78 as 11 times with remainder, etc. 784/7 = 112.

Subtract 5 from both sides: x = 12 − 5 = 7.

Follow PEMDAS: multiply before add. 4×2 = 8; 3+8 = 11.

Area = length × width = 9×4 = 36 cm².

Mode is the most frequent value; here 3 occurs most often.

5 goes into 45 as 9 times, remainder 0, then 5 into 5 is 1. 455/5 = 91.

Divide both sides by 2: y = 14/2 = 7.

Compute parentheses first: (1+2)=3. Then 6÷2×3 = 3×3 = 9.

Perimeter P=2(L+W)=26 => L+W=13 => W=13−7=6.

 
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