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Rumbo al Recreo: Matemáticas en Freiburg 1945

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Rumbo al Recreo: Matemáticas en Freiburg 1945

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About this activity

Aventuras numéricas para avanzar al recreo

Created by

Víctor de Jesús González Cárabez
Víctor de Jesús González Cárabez
Mexico

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Rumbo al Recreo: Matemáticas en Freiburg 1945
 

Rumbo al Recreo: Matemáticas en Freiburg 1945Online version

Aventuras numéricas para avanzar al recreo

by Víctor de Jesús González Cárabez
1

Nivel 1: -6 + 2 = ?

2

Ley de signos: (-5) + (+8) es

3

Operaciones combinadas: 6 + (-3) × 2 =

4

Ecuación de primer grado: x + 5 = 12, x = ?

5

Ecuación: 3x = 18, x = ?

6

Problema contextualizado: Si deuda es -12 y llega 20, balance es

7

Operación de enteros: -8 + 5 + 3 = ?

8

Orden de operaciones simple: 2 + 3 × 4 = ?

9

Problema: en la clase, si -2 + 9 - 4 = ?

10

(4x-8y+8)+(2x-1y-5)

11

Si la temperatura es de -4°C y aumenta 7°C, ¿cuál es la temperatura actual?

12

Una magnitud pasa de 5 a 8. ¿Cuánto es la ganancia?

13

Signos: ¿(positivo)×(negativo) = ?

14

Resolución básica: 3x = 12, x = ?

15

4) Ecuaciones simples: resuelve 3x + 5 = 14, x = ?

16

6) Desafío final: resuelve -2x + 6 = 2, x = ?

17

8) Ganancias y pérdidas: si gana 5 y pierde 8, resultado neto es...

18

10) Desafío final: resuelve 2x - 4 = 6, x = ?

Explicación

Pista: restas bos caracteres positivos.

Observa el signo dejando el mayor en valor.

Primero realiza la multiplicación.

Despeja x restando 5.

Divide ambos lados entre 3.

Suma y resta según signo.

Asocia sumas y restas secuencialmente.

Primero la multiplicación, luego la suma.

Suma de enteros mantiene el signo mayor.

Ganancia = 8 − 5 = 3.

El producto de signos opuestos es negativo.

Divide ambos lados por 3 → x = 12/3 = 4.

Resta 5 a ambos lados: 3x = 9, x = 3.

-2x = -4 → x = 2.

5 - 8 = -3 de pérdida neta.

2x = 10 → x = 5.

 
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