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Examen de Razones Trigonométricas y Medidas de Tendencia Central

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Examen de Razones Trigonométricas y Medidas de Tendencia Central

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Quiz práctico de trigonometría y MTC y D

Created by

Esperanza Hernandez
Esperanza Hernandez
Mexico

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Examen de Razones Trigonométricas y Medidas de Tendencia Central
 

Examen de Razones Trigonométricas y Medidas de Tendencia CentralOnline version

Quiz práctico de trigonometría y MTC y D

by Esperanza Hernandez
1

En un triángulo rectángulo, si el ángulo agudo mide 30°, la hipotenusa es 10 cm. ¿Cuál es la longitud del cateto opuesto?

2

Con un ángulo agudo de 45°, la hipotenusa mide 10 cm. ¿Cuál es la longitud del cateto opuesto?

3

Si un ángulo agudo tiene un cos = 0.6, ¿cuál es su medida en grados?

4

Calcula la media aritmética, la mediana y la moda de: 2, 4, 6, 6, 8, 10.

5

La mediana de: 1, 9, 3, 7, 12 es:

6

La moda de: 4, 4, 6, 6, 6, 9 es:

7

Rango de: 2, 7, 5, 10, 6 es:

8

Desviación media de: 2, 4, 6, 8, 7, 3, 15, 19 es:

9

En un triángulo rectángulo, ángulo de 60°, hipotenusa 5 cm. ¿Cuál es el cateto adyacente?

10

Encuentra la medida del ángulo X cuando el cateto opuesto mide 18 y el cateto adyacente mide √360

Explicación

Seno30° = opuesto/hipotenusa → opuesto = 10·0.5 = 5 cm.

En 45°, cateto opuesto = 10·sin45° ≈ 7.07 cm.

Arccos(0.6) ≈ 53.13°.

Media = (2+4+6+6+8+10)/6 = 6. Mediana = 6+6/2=6 Moda=6 se repite mas

Ordenados ya, la mediana es el valor central.

La moda es el valor que más se repite.

Rango = máximo − mínimo = 10 − 2 = 8.

Media = 8; desviaciones absolutas: 6,4,2,0,1,5,7,11; Desviación Media = 36/8=5.2.

Adyacente = hipotenusa·cos60° = 5·0.5 = 2.5 cm.

usamos Tan X=Co/Ca y el resultado lo convertimos a grados usando la calculadora o la tabla de razones trigonométricas

 
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