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Quiz de Análisis de Circuitos en DC

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Quiz de Análisis de Circuitos en DC

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Circuits DC: conceptos y cálculos

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LOPEZ-FG ANCASI
LOPEZ-FG ANCASI
Bolivia

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Quiz de Análisis de Circuitos en DC
 

Quiz de Análisis de Circuitos en DCOnline version

Circuits DC: conceptos y cálculos

by LOPEZ-FG ANCASI
1

En un circuito DC, si R = 4 Ω y V = 12 V, ¿cuál es la corriente I?

2

La ley de Ohm establece I = V/R. Si V = 9 V y R = 3 Ω, ¿cuál es I?

3

Dos resistencias en paralelo de 6 Ω y 3 Ω conectadas a 12 V. ¿Corriente total?

4

Con fuente de 5 V y R = 10 Ω, ¿cuánta potencia disipa la resistencia?

5

Fuente de 10 V y dos resistencias en serie de 2 Ω y 8 Ω. ¿La corriente en el lazo?

6

La Ley de Kirchhoff de voltajes (KVL) indica que la suma de todas las caídas de voltaje en un lazo es cero. ¿Verdadero o falso?

7

Si duplica la fuente manteniendo R constante, ¿qué ocurre con I?

8

El teorema de Thevenin dice que cualquier circuito lineal visto desde dos terminales es equivalente a una fuente y una resistencia. ¿Verdadero o falso?

9

En un corto entre dos nodos de un circuito, la corriente tiende a seguir el camino de menor resistencia. ¿Qué pasa con la resistencia del resistor aislado?

10

¿Qué unidad se usa para la resistencia eléctrica?

11

Seleccione la expresión correcta de la Segunda Ley de Kirchhoff.

12

Si un resistor de 20 Ω es atravesado por una corriente de 3 A, el voltaje será:

13

Seleccione el procedimiento correcto para calcular una corriente utilizando la Ley de Ohm.

14

¿Qué ocurre en un circuito abierto?

Explicación

Aplicar I = V/R: 12/4 = 3 A.

I = 9/3 = 3 A.

Reac de paralelo: Req = (6·3)/(6+3) = 2 Ω; I = 12/2 = 6 A.

P = V^2/R = 25/10 = 2.5 W.

I = V/(R1+R2) = 10/10 = 1 A.

En un lazo cerrado, las sumas algebraicas de voltajes son cero.

I = V/R; al duplicar V, I duplica.

Thevenin simplifica a una fuente ideal más Rv.

El cortocircuito reduce la ruta a baja resistencia, desviando corriente.

La resistencia se mide en ohmios, Ω.

 
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