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Electricidad: Rápido de Electricidad

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Electricidad: Rápido de Electricidad

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Quiz de conceptos y cálculos eléctricos

Created by

Patricia Nava Aguilar
Patricia Nava Aguilar
Mexico

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Electricidad: Rápido de Electricidad
 

Electricidad: Rápido de ElectricidadOnline version

Quiz de conceptos y cálculos eléctricos

by Patricia Nava Aguilar
1

En un circuito circula 5 A a través de una resistencia de 10 Ω. ¿Cuál es el voltaje del circuito?

2

Un dispositivo funciona con 36 V y 3 A. ¿Cuál es el valor de la resistencia?

3

Una aparato tiene resistencia de 15 Ω y recibe 90 V. ¿Cuál es la intensidad de corriente?

4

Dos cargas de 4 C y -2 C separadas 0.5 m. Calcula la fuerza eléctrica en el vacío. (k ≈ 9×10^9 N·m^2/C^2)

5

Fuerza entre dos cargas es 24 N. Una carga es 3 C y la distancia 0.4 m, determina q2 en agua. (ε_r ≈ 80)

6

Dos cargas 5×10^-6 C y 8×10^-6 C generan 18 N en aire. ¿A qué distancia se encuentran?

7

Una carga de prueba de 4×10^-6 C experimenta una fuerza de 2 N. ¿Cuál es el campo eléctrico?

8

Una partícula con carga 6×10^-6 C está en un campo de 2×10^5 N/C. ¿Qué fuerza actúa?

9

En un campo de 8×10^4 N/C, una carga sufre una fuerza de 0.8 N. ¿Cuál es la carga?

10

Explica, en una frase, la diferencia entre corriente eléctrica y campo eléctrico.

Explicación

Usa V = I·R. 5 A × 10 Ω = 50 V.

Aplicar R = V/I. 36 V / 3 A = 12 Ω.

Ley de Ohm: I = V/R. 90 V / 15 Ω = 6 A.

F = k|q1 q2|/r^2, magnitud ≈ (9×10^9×8)/0.25 ≈ 2.88×10^11 N.

En agua, F ≈ (k/q) q1 q2 / r^2 con k_eff ≈ 8.99e9/80. Resolviendo q2 ≈ F r^2 /(k_eff q1).

F = k q1 q2 / r^2. r^2 = k q1 q2 / F ≈ (9×10^9×40×10^-12)/18 ≈ 0.02 m^2, r ≈ 0.141 m.

E = F/q = 2 N / 4×10^-6 C = 5×10^5 N/C.

F = qE = (6×10^-6 C)(2×10^5 N/C) = 1.2 N.

q = F/E = 0.8 / 8×10^4 = 1×10^-5 C.

La corriente es el movimiento de cargos; el campo es la influencia que ejerce la distribución de cargas para producir fuerzas.

 
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