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Factorización por agrupación

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Factorización por agrupación

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Juego sobre factorizar por agrupación

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duver fernando meneses
duver fernando meneses
Colombia

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Factorización por agrupación
 

Factorización por agrupaciónOnline version

Juego sobre factorizar por agrupación

by duver fernando meneses
1

Factoriza por agrupación: x^3+2x^2+3x+6.

2

Factoriza por agrupación: 3x+3y+2x+2y.

3

Factoriza por agrupación: x^2+4x+xy+4y.

4

Factoriza por agrupación: a^2b+ab^2.

5

Factoriza por agrupación: pq+pr+sq+sr.

6

Factoriza por agrupación: 2x^2+6x+4.

7

Factoriza por agrupación: x^3+3x^2+2x+6.

8

Factoriza por agrupación: y^3+2y^2+y+2.

9

Factoriza por agrupación: x^2+xz+xy+yz.

10

Factoriza por agrupación: ab+ac+db+dc.

Explicación

Agrupa x^3+2x^2 y 3x+6 para sacar x^2 y 3, luego (x^2+3)(x+2).

Agrupa términos con x+y: (3x+3y)+(2x+2y)=3(x+y)+2(x+y)=5(x+y).

Agrupa: x^2+4x + xy+4y = x(x+4) + y(x+4) = (x+y)(x+4).

Revisa que ab es común: a^2b+ab^2 = ab(a+b).

Agrupa en (p+ s)(q+ r) al reorganizar términos: pq+pr+sq+sr.

Descompón en 2x^2+4x+2x+4 y factoriza por regrouping: 2(x^2+3x+2)=2(x+1)(x+2).

Agrupa: x^3+3x^2 + 2x+6 = x^2(x+3)+2(x+3) = (x+3)(x^2+2).

Agrupa: y^3+2y^2 + y+2 = y^2(y+2)+1(y+2) = (y+2)(y^2+1).

Reorganiza como x^2+xz+xy+yz = x(x+z) + y(x+z) = (x+y)(x+z).

Agrupa: ab+ac+db+dc = a(b+c)+d(b+c) = (a+d)(b+c).

 
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