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Ley del Seno: Quiz Esencial

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Ley del Seno: Quiz Esencial

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Triángulos y proporciones

Created by

Belen Tamami
Belen Tamami
Ecuador

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Ley del Seno: Quiz Esencial
 

Ley del Seno: Quiz EsencialOnline version

Triángulos y proporciones

by Belen Tamami
1

¿Qué expresa la ley del seno para un triángulo?

2

Si conocemos dos ángulos y un lado, ¿qué podemos hallar?

3

¿Qué relación usa la ley del seno entre un lado y su ángulo opuesto?

4

¿Qué caso puede dar dos soluciones al resolver con la ley del seno?

5

¿Qué fórmula da R usando la ley del seno?

6

¿Qué fórmula se usa para hallar otro lado b si ya tienes a, A y B?

7

Si A=60° y a=6, ¿qué relación permite hallar C?

8

¿Qué relación se iguala para relacionar dos lados y sus ángulos opuestos?

9

¿Qué se puede deducir si a/sin A = b/sin B?

10

¿Qué condición se usa para confirmar que la ley del seno aplica bien?

Explicación

Relaciona cada lado con su ángulo opuesto mediante senos.

Con A, B y a podemos obtener b y c por la ley del seno.

a/sin A = b/sin B = c/sin C, constante en un triángulo.

Ocurre cuando conocemos dos lados y un ángulo no incluido.

El radio circunscrito está relacionado con cualquier lado y su ángulo opuesto.

Deriva de a/sin A = b/sin B.

De la ley del seno, sin C = c sin A / a; con c conocido se obtiene C.

Es la forma esencial para comparar dos pares lado-ángulo.

El cociente es constante para todos los lados y sus ángulos opuestos.

La ley del seno requiere información adecuada para determinar los demás elementos.

 
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