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Quiz: Ley de Gay-Lussac (gases ideales)

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Quiz: Ley de Gay-Lussac (gases ideales)

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About this activity

Prueba sobre P y T a volumen constante

Created by

Samuel Guerrero Vanegas Guerrero Vanegas
Samuel Guerrero Vanegas Guerrero Vanegas
El Salvador

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Quiz: Ley de Gay-Lussac (gases ideales)
 

Quiz: Ley de Gay-Lussac (gases ideales)Online version

Prueba sobre P y T a volumen constante

by Samuel Guerrero Vanegas Guerrero Vanegas
1

¿Qué relación describe la ley de Gay-Lussac para gases ideales manteniendo el volumen constante?

2

¿Cuál es la fórmula típica de la ley de Gay-Lussac para relacionar P y T entre dos estados?

3

Si la temperatura de un gas seco es el doble (en K) y el volumen no cambia, ¿qué le pasa a la presión?

4

¿Qué unidad es necesaria para T en la ley de Gay-Lussac?

5

Si un gas pasa de 300 K a 450 K a volumen constante, ¿cómo cambia P?

6

Una botella de gas a 1 atm y 298 K se calienta a 398 K, manteniendo el volumen. ¿Qué ocurre con P?

7

La ley de Gay-Lussac se aplica cuando el volumen se mantiene:

8

¿Qué sucede con la presión si sube la temperatura en un gas a volumen constante?

9

En un experimento, P1 = 2 atm, T1 = 300 K. Si T2 = 600 K y V constante, ¿P2?

10

¿Qué error común cometen al aplicar la ley de Gay-Lussac?

Explicación

La presión aumenta linealmente con la temperatura en Kelvin cuando V es constante.

Se usa P1/T1 = P2/T2 cuando V es constante.

Al duplicar T en Kelvin, P también se duplica si V es constante.

La relación P ∝ T usa T en Kelvin para evitar errores.

P ∝ T, 450/300 = 1.5.

Relación P2 = P1 * (T2/T1) = 1 atm * (398/298) ≈ 1.34 atm.

La clave es V constante para P ∝ T.

A mayor temperatura, mayor energía de las moléculas, mayor colisiones.

P2 = P1*(T2/T1) = 2*(600/300) = 4 atm.

Debes usar T en Kelvin; Celsius no es adecuado para proporciones.

 
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