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Ion-Electrón en Medio Ácido

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Ion-Electrón en Medio Ácido

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About this activity

Ejercicios de redox en ácido

Created by

Angelina Quiñonez
Angelina Quiñonez
Ecuador

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Ion-Electrón en Medio Ácido
 

Ion-Electrón en Medio ÁcidoOnline version

Ejercicios de redox en ácido

by Angelina Quiñonez
1

Balancea Fe2+ → Fe3+ en medio ácido

2

Balancea la semireacción: MnO4- + 8 H+ → Mn2+ + 4 H2O

3

Qué se necesita para balancear O en ácido: H2O o H+

4

Balancea la oxidación de oxígeno en H2SO4: MnO4- → Mn2+ en medio ácido

5

Si se oxida Fe2+ a Fe3+ en medio ácido, ¿cuántos electrones se pierden?

6

Balancea: Cr2O7^2- + 14 H+ + 6 e- → 2 Cr3+ + 7 H2O

Explicación

Perdemos un electrón al pasar de Fe2+ a Fe3+.

Incluye 5 e- para balancear carga.

En ácido, balancea O con H2O y luego H con H+.

La semireacción correcta requiere 8 H+ y 5 e-.

Pérdida de un electrón para pasar de +2 a +3.

Cromato se reduce de Cr6+ a Cr3+ con 6 e- ganados.

 
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