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Desafío: 2ª Ley de Newton

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Desafío: 2ª Ley de Newton

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Problemas de F=ma y factores

Created by

Morales Morales
Morales Morales
Peru

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Desafío: 2ª Ley de Newton
 

Desafío: 2ª Ley de NewtonOnline version

Problemas de F=ma y factores

by Morales Morales
1

Si una masa de 5 kg recibe una fuerza total de 15 N, ¿cuál es la aceleración?

2

Una caja de 2 kg es empujada con 7 N. ¿Qué aceleración tiene la caja?

3

Si la aceleración es -2 m/s^2 y la masa es 4 kg, ¿qué fuerza actúa?

4

Dos cuerpos de 3 kg y 5 kg, con una fuerza horizontal de 6 N en el conjunto. ¿La aceleración común?

5

Tres masas 2 kg, 3 kg y 4 kg en un sistema, con fuerza total 10 N sobre el conjunto. ¿La aceleración?

6

Una fuerza de 0 N actúa sobre una masa de 9 kg. ¿Qué aceleración tiene?

7

Un bloque de 6 kg tiene una fuerza de -12 N. ¿Qué dirección tiene la aceleración?

8

Si la masa aumenta pero la fuerza se mantiene, ¿qué ocurre con la aceleración?

9

Una masa de 0.5 kg recibe 2 N. ¿Qué aceleración tiene?

10

Masa m1=2 kg y m2=3 kg unidos, se aplican 8 N a m1 y 4 N a m2. ¿La aceleración del sistema?

Explicación

F = ma ⇒ a = F/m = 15/5 = 3.

a = F/m = 7/2 = 3.5 m/s^2.

F = ma ⇒ F = 4×(-2) = -8 N.

a = F/(m1+m2) = 6/8 = 0.75 m/s^2.

a = F/(m1+m2+m3) = 10/9 ≈ 1.11 m/s^2.

Sin fuerza neta, la aceleración es cero.

F = ma ⇒ si F es negativa, a también lo es (dirección opuesta).

a = F/m; mayor masa ⇒ menor aceleración.

a = F/m = 2/0.5 = 4 m/s^2.

F_total = 8+4 =12 N; a = F_total/(m1+m2)=12/5=2.4 m/s^2.

 
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