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Recta: Ecuaciones

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Recta: Ecuaciones

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Desafío de ecuaciones lineales

Created by

OROZCO DIAZ DARWIN ANDRES
OROZCO DIAZ DARWIN ANDRES
Ecuador

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Recta: Ecuaciones
 

Recta: EcuacionesOnline version

Desafío de ecuaciones lineales

by OROZCO DIAZ DARWIN ANDRES
1

Dada la recta y = 2x + 5, ¿cuál es su pendiente m y su ordenada al origen b?

2

Convierte la recta 3x - 4y = 12 a la forma pendiente-intersección y = mx + b.

3

La recta que pasa por A(2, -1) y B(5, 3) tiene pendiente m = ?

4

Escribe la ecuación en forma general Ax + By = C para la recta y = -x + 4.

5

Si una recta tiene pendiente m = -3 y pasa por (0, 7), su ecuación en forma punto-pendiente es:

6

Geometría de la recta: ¿qué significa una recta con pendiente m = 0?

7

Dada la ecuación 4x - 5y = 20, ¿cuál es su pendiente m?

8

Transforma y = 3x + 7 a la forma general Ax + By = C.

9

Si la recta pasa por (1,2) y tiene m = 4, ¿cuál es su ecuación en forma punto-pendiente?

10

La ecuación estándar de la recta con pendiente 2 que pasa por el origen es:

Explicación

La pendiente es la pendiente m y la intersección con el eje y es b.

Despeja y: 3x - 4y =12 → -4y = -3x +12 → y = (3/4)x -3.

Pendiente m = (3 - (-1)) / (5 - 2) = 4/3 ≈ 1.33. (A) incorrecto podría ser confusión; ajustemos: La correcta es 4/3.

En y = -x + 4, mueve términos: x + y = 4.

Con punto (0,7) y m = -3, forma y - y1 = m(x - x1).

Pendiente 0 implica horizontal.

Despeja y: -5y = -4x + 20 → y = (4/5)x -4.

Traslada: y - 3x = 7 → -3x + y = 7.

Aplicar y - y1 = m(x - x1) con (1,2) y m=4.

Pasa por (0,0) y m = 2 → y = 2x; en forma estándar 2x - y = 0.

 
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