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Lingkaran Pusat (0,0) dan Titik (a,b)

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Quiz persamaan lingkaran sederhana

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Lingkaran Pusat (0,0) dan Titik (a,b)
 

Lingkaran Pusat (0,0) dan Titik (a,b)Online version

Quiz persamaan lingkaran sederhana

by IRA RISMAYANTI
1

Persamaan lingkaran dengan pusat (0,0) yang melalui (3,4) adalah...

2

Jika circle pusat (0,0) melalui (5,12), r^2 = ?

3

Persamaan x^2+y^2=a^2+b^2 menggambarkan lingkaran melalui titik (a,b) dengan pusat origin. Benar?

4

Diberikan a=6, b=8. Persamaan lingkaran pusat (0,0) yang melalui (6,8) adalah...

5

Titik (-3,4) berada di lingkaran dengan pusat (0,0). Persamaannya adalah...

6

Untuk lingkaran x^2+y^2=r^2, jika r^2=a^2+b^2 dengan a=9,b=12, maka r^2 = ?

7

Pilih persamaan yang benar untuk lingkaran pusat (0,0) melalui (1,7).

8

Lingkaran pusat (0,0) dengan titik pada lingkaran (a,b) mematuhi: r^2 = ?

9

Kalimat mana yang benar tentang lingkaran centered (0,0) dan titik (a,b)?

10

Soal literasi: jika a=0 atau b=0, persamaan tetap benar?

Feedback

r^2 = 3^2+4^2 = 25; persamaan x^2+y^2=r^2.

r^2 = 5^2+12^2 = 169.

Karena jarak dari origin ke (a,b) adalah sqrt(a^2+b^2), jadi r^2 = a^2+b^2.

r^2=6^2+8^2=100.

r^2=(-3)^2+4^2=25.

r^2=9^2+12^2=81+144=225.

r^2=1^2+7^2=50.

Jarak dari origin ke (a,b) adalah sqrt(a^2+b^2). r^2 = a^2+b^2.

Esensi: jarak dari pusat ke (a,b) adalah sqrt(a^2+b^2).

Gerakannya tetap r^2=a^2+b^2; jika salah satu nol, r^2 tetap sama.

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