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Reto: Sistemas 2x2 y dígitos

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Reto: Sistemas 2x2 y dígitos

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Resolver 2x2 y listar dígito del 54298

Created by

Yzel Wlly Alay Gomez Espindola
Yzel Wlly Alay Gomez Espindola
Colombia

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Reto: Sistemas 2x2 y dígitos
 

Reto: Sistemas 2x2 y dígitosOnline version

Resolver 2x2 y listar dígito del 54298

by Yzel Wlly Alay Gomez Espindola
1

Sistema: 2x + y = 5; 3x + 2y = 4. ¿Cuál es x?

2

Sistema: x + y = 4; 2x - y = 2. ¿Cuál es x?

3

Sistema: 4x + y = 9; x + y = 3. ¿Cuánto vale x?

4

Sistema: x + y = 4; 2x + 3y = 9. ¿Valor de x?

5

Sistema: 3x + 2y = 7; x - y = 1. ¿Qué x resulta?

6

Sistema: 2x + y = 5; 3x + y = 7. ¿Valor de x?

7

Sistema: x - 2y = -3; 3x + y = 2. ¿Qué x?

8

Sistema: 4x + 2y = 12; x + y = 3. ¿Cuánto vale x?

9

Sistema: x + 3y = 7; 2x - y = 1. ¿Valor de x?

10

Sistema: 5x + y = 11; 2x + 3y = 7. ¿Cuánto vale x?

Explicación

Solución por sustitución: de la primera, y=5-2x; en la segunda, 3x+2(5-2x)=4 → -x=-6 → x=6.

Suma de ecuaciones tras aíslar y en ambas: x obtenida como 2.

Resta estas ecuaciones para eliminar y: (4x+y)-(x+y)=9-3 → 3x=6 → x=2.

Despeja x=4-y y sustituye en 2x+3y=9 para obtener x=3.

De x=y+1; sustituye en 3(y+1)+2y=7 → 5y=4 → y=0.8, luego x=1.8 (aprox). El dato correcto es x=0.8/0.8?

Restando ecuaciones da (2x+y)-(3x+y)=-2x=-2 → x=2.

Resolviendo: x= (11/7) ≈ 1.5714; se obtiene al sustituir y de la primera en la segunda.

De la segunda, y=3-x. Sustituyendo en la primera: 4x+2(3-x)=12 → 2x=6 → x=3.

De 2x - y =1 ⇒ y=2x-1. Sustituyendo en la primera: x+3(2x-1)=7 → 7x=10 → x≈1.4286.

De la segunda, y=(7-2x)/3. Sustituyendo en la primera: 5x+(7-2x)/3=11 → resuelve para x → x=2.

 
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