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Quiz Teorema Sisa & Faktor

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Quiz Teorema Sisa & Faktor

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Teorema sisa/faktor polinomial

Created by

Ika Kris
Ika Kris
Indonesia

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Quiz Teorema Sisa & Faktor
 

Quiz Teorema Sisa & FaktorOnline version

Teorema sisa/faktor polinomial

by Ika Kris
1

Jika f(x) = x^3 - 4x^2 + 5x - 2, tentukan sisa ketika dibagi dengan (x-1).

2

Syarat f(a)=0 menunjukkan apa pada teorema faktor?

3

Hitung sisa f(x)=2x^2+3x-1 saat dibagi dengan (x+1).

4

Polinomial f(x)=x^3-6x^2+11x-6 dibagi (x-2). sisa adalah?

5

Jika f(3) ≠ 0, apa yang bisa disimpulkan tentang (x-3)?

6

Untuk f(x)=4x^3+x^2-5x+2, sisa dibagi (x-2) adalah?

7

Teorema sisa berguna untuk mengecek faktor tanpa pembagian panjang, benar atau salah?

8

Jika f(x)=x^2-5x+6 dibagi (x-3), sisa?

9

Dengan teorema sisa, jika f(4)=7 maka sisa saat dibagi (x-4) adalah?

10

Untuk f(x)=ax^2+bx+c, jika f(1)=0 maka (x-1) adalah?

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Rumus sisa: sisa = f(a) dengan pembagi (x-a). ganti x=a=1.

Jika f(a)=0, maka (x-a) membagi f(x) tanpa sisa.

Sisa = f(a) dengan a = -1.

Karena f(2)=0, (x-2) adalah faktor.

f(3) ≠ 0 berarti (x-3) tidak membagi f(x) tanpa sisa.

Evaluasi f pada x=2 memberikan sisa.

Sisa bisa cepat diperoleh dengan f(a).

Faktor (x-3) jika f(3)=0; substitusi: 9-15+6=0.

Sisa sama dengan nilai f(a) pada a=4.

f(1)=0 ⇒ (x-1) faktor polinomial.

 
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