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Examen: Factorización avanzada

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Examen: Factorización avanzada

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Factorización de binomios al cuadrado, diferencias y cubos

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JUAN CARLOS NAVARRO BEJINES
JUAN CARLOS NAVARRO BEJINES
Mexico

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Examen: Factorización avanzada
 

Examen: Factorización avanzadaOnline version

Factorización de binomios al cuadrado, diferencias y cubos

by JUAN CARLOS NAVARRO BEJINES
1

Factoriza x^2 - 9.

2

Factoriza x^2+6x+9.

3

Factoriza a^3 - b^3.

4

Factoriza 4x^2-25.

5

Factoriza x^2+4x-5.

6

Factoriza 9x^2+12x+4.

7

Factoriza 8y^3-1.

8

¿Cuál es la forma de factorizar una diferencia de cuadrados?

9

Factoriza 27z^3-8.

10

Factoriza a^2 - b^2.

Explicación

Es una diferencia de cuadrados: (a^2-b^2)=(a-b)(a+b). Las otras opciones no descomponen correctamente la expresión.

Es un trinomio que es un cuadrado perfecto: (x+3)^2 = x^2+6x+9. Las otras opciones no coinciden con la expansión.

La fórmula correcta es (a-b)(a^2+ab+b^2). Las otras son factorizaciones incorrectas de a^3-b^3.

Es una diferencia de cuadrados: (2x)^2-(5)^2=(2x-5)(2x+5). Las demás no descomponen correctamente.

Se buscan raíces que sumen 4 y multipliquen -5; 5 y -1 cumplen: (x+5)(x-1). Las otras fallan en el producto o la suma.

Es un trinomio cuadrado perfecto: (3x+2)^2. Las otras no coinciden con la expansión.

Es diferencia de cubos: (2y)^3-1^3. El segundo factor debe ser 4y^2+2y+1; las otras opciones están mal.

La diferencia de cuadrados se factoriza como (a-b)(a+b). Las demás no es la fórmula correcta.

Es diferencia de cubos: (3z)^3-2^3. El primer factor correcto es (3z-2) y el segundo debe ser 9z^2+6z+4.

Es la diferencia de cuadrados: a^2-b^2=(a-b)(a+b). Las otras no dan la factorización correcta.

 
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