9.3 Monohybrid crossingOnline version Concept of the Punnett square and monohybrid crossing. by Jorge Arizpe 1 Gene A (yellow) is dominant over gene a (green).The crossing of AA and aa will give: a 50 % yellows and 50 % greens b 100 % of yellow c 25 % yellow, 50 % greenish yellow and 25 % greens d 100 % Greens 2 Gene A (yellow) is dominant over gene a (green). The crossing of 2 heterozygous Aa will give: a 50 % yellows and 50 % greens b 25 % Yellow, 50 % Greenish yellow and 25 % greens c 75 % Yellows and 25 % Greens d 100 % Greens 3 Partial dominance for antennae in insects: A Long, AB Medium, and B Short. Crossing of AA x BB a 100 % Long b 50 % Long and 50 % Short c 25 % Long, 50 % Medium, 25 % Short d 100 % Medium 4 Partial dominance for antennae in insects :A Long, AB Medium, and B Short. Crossing of AB x AB a 25 % Long, 50 % Medium, 25 % Short b 50 % Long and 50 % Short c 100 % Medium d 100 % Long 5 The color of the carnation flowers shows a partial or incomplete dominance. The R allele codes for red, the B allele for white and the heterozygote RB turns pink. At the crossing of two RB heterozygotes one might expect the color of their offspring to be: a 50 % Red, 50 % White b 25 % red, 50 % pink and 25 % white c 100 % Pink d 33 % Red, 33 % White and 33 % Pink 6 The color of the carnation flowers shows a partial or incomplete dominance. The R allele codes for red, the B allele for white and the heterozygote RB turns pink. At the intersection of two homozygous BBs and a heterozygous BR, how would you expect the color of the offspring to be? a 25 % White, 50 % Pink and 25 % Red b 50 % White and 50 % Red c 50 % White and 50 % Pink d 33 % White, 33 % Red and 33 % Pink 7 Some specimens of the Bobtail breed do not have a tail. Two dogs without a tail are crossed and the resulting offspring are: 75% puppies without a tail and 25% puppies with a tail. It can be concluded that the allele coding for "NO TAIL" is: a Imposible to know b Recessive c Codominant d Dominant 8 Daltonism (which is a condition that does not allow to distinguish some colors) is due to a recessive gene linked to the X chromosome. This recessive gene for color blindness is represented by dX and the chromosome of an un-impaired vision by X. What would be the possible phenotype of children resulting from the marriage between a carrier woman and a visually un-impaired man? a 25 % carrier woman, 25 % daltonic woman, 25% normal man and 25 % carrier man. b 50 % carrier woman y 50 % normal man c 25 % normal woman, 25% carrier woman, 25 % normal man and 25 % daltonic man d 50 % normal woman and 50 % daltonic man 9 Daltonism (which is a condition that does not allow to distinguish some colors) is due to a recessive gene linked to the X chromosome. This recessive gene for color blindness is represented by dX and the chromosome of an un-impaired vision by X. What would be the possible phenotype of children resulting from the marriage between a carrier woman and a Daltonic man? a 25 % carrier woman, 25 % daltonic woman y 50 % daltonic man b 25 % normal woman, 25 % carrier woman, 25 % normal man and 25 % daltonic man c 25 % carrier woman, 25 % daltonic woman, 25 % normal man and 25 % daltonic man d 50 % daltonic woman and 50 % daltonic man 10 DNA segment that contains the information for a specific trait. a Genotype b Genome c Chromosome d Gen 11 It is the name given to the variant forms of a gene a Alleles b Genes c Chromosomes d Genotypes 12 This cell contains the total chromosomes of a species. It is represented as 2n. a Gamete b Haploid c Diploid d Complete 13 This cell contains only half of a species' chromosomes. It is represented as n a Incomplete b somatic cell c Diploid d Haploid 14 When an organism has two identical alleles for the same gene, it is said to be: a Gay b Zygote c Homozygous d Heterozygous 15 Which one of these represents a heterozygous genotype? a b c d
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